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1214445054233 is a prime number
BaseRepresentation
bin10001101011000010100…
…100001110100100011001
311022002200202121220012002
4101223002210032210121
5124344140413213413
62325524112130345
7153512036431535
oct21530244164431
94262622556162
101214445054233
11429052633144
1217744b2369b5
138a6a2181388
1442acab72bc5
15218cce31958
hex11ac290e919

1214445054233 has 2 divisors, whose sum is σ = 1214445054234. Its totient is φ = 1214445054232.

The previous prime is 1214445054197. The next prime is 1214445054257. The reversal of 1214445054233 is 3324505444121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1208937633289 + 5507420944 = 1099517^2 + 74212^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214445054233 is a prime.

It is a super-2 number, since 2×12144450542332 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1214445056233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607222527116 + 607222527117.

It is an arithmetic number, because the mean of its divisors is an integer number (607222527117).

Almost surely, 21214445054233 is an apocalyptic number.

It is an amenable number.

1214445054233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214445054233 is an equidigital number, since it uses as much as digits as its factorization.

1214445054233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 38.

The spelling of 1214445054233 in words is "one trillion, two hundred fourteen billion, four hundred forty-five million, fifty-four thousand, two hundred thirty-three".