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1214453113142 = 2896336774587
BaseRepresentation
bin10001101011000011000…
…010111110000100110110
311022002201022210022221012
4101223003002332010312
5124344144444110032
62325525000552222
7153512165065103
oct21530302760466
94262638708835
101214453113142
114290571379a5
12177451a82672
138a6a3a43569
1442acbc6daaa
15218cd9c46b2
hex11ac30be136

1214453113142 has 8 divisors (see below), whose sum is σ = 1821700262376. Its totient is φ = 607219692352.

The previous prime is 1214453113129. The next prime is 1214453113151. The reversal of 1214453113142 is 2413113544121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×12144531131422 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1214453113099 and 1214453113108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3208028 + ... + 3566559.

It is an arithmetic number, because the mean of its divisors is an integer number (227712532797).

Almost surely, 21214453113142 is an apocalyptic number.

1214453113142 is a deficient number, since it is larger than the sum of its proper divisors (607247149234).

1214453113142 is an equidigital number, since it uses as much as digits as its factorization.

1214453113142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6864222.

The product of its digits is 11520, while the sum is 32.

Adding to 1214453113142 its reverse (2413113544121), we get a palindrome (3627566657263).

The spelling of 1214453113142 in words is "one trillion, two hundred fourteen billion, four hundred fifty-three million, one hundred thirteen thousand, one hundred forty-two".

Divisors: 1 2 89633 179266 6774587 13549174 607226556571 1214453113142