12145000433 has 2 divisors, whose sum is σ = 12145000434. Its totient is φ = 12145000432.

The previous prime is 12145000381. The next prime is 12145000463. The reversal of 12145000433 is 33400054121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7699711504 + 4445288929 = 87748^2 + 66673^2 .

It is a cyclic number.

It is not a de Polignac number, because 12145000433 - 2¹⁰ = 12144999409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12145000399 and 12145000408.

It is not a weakly prime, because it can be changed into another prime (12145000463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6072500216 + 6072500217.

It is an arithmetic number, because the mean of its divisors is an integer number (6072500217).

Almost surely, 2^12145000433 is an apocalyptic number.

It is an amenable number.

12145000433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12145000433 is an equidigital number, since it uses as much as digits as its factorization.

12145000433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 12145000433 its reverse (33400054121), we get a palindrome (45545054554).

The spelling of 12145000433 in words is "twelve billion, one hundred forty-five million, four hundred thirty-three", and thus it is an aban number.