Base | Representation |
---|---|
bin | 11011100111010101001000… |
… | …111001110101110010011111 |
3 | 120221000111201020201022021021 |
4 | 123213111020321311302133 |
5 | 111404314111404213241 |
6 | 1110145211011145011 |
7 | 34403321356254316 |
oct | 3347251071656237 |
9 | 527014636638237 |
10 | 121450013351071 |
11 | 35774730383399 |
12 | 117559ab8a5167 |
13 | 529c8c17994b2 |
14 | 21dc2d7a8327d |
15 | e092d83e60d1 |
hex | 6e7548e75c9f |
121450013351071 has 2 divisors, whose sum is σ = 121450013351072. Its totient is φ = 121450013351070.
The previous prime is 121450013350999. The next prime is 121450013351141. The reversal of 121450013351071 is 170153310054121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121450013351071 - 239 = 120900257537183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121450013355071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60725006675535 + 60725006675536.
It is an arithmetic number, because the mean of its divisors is an integer number (60725006675536).
Almost surely, 2121450013351071 is an apocalyptic number.
121450013351071 is a deficient number, since it is larger than the sum of its proper divisors (1).
121450013351071 is an equidigital number, since it uses as much as digits as its factorization.
121450013351071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12600, while the sum is 34.
The spelling of 121450013351071 in words is "one hundred twenty-one trillion, four hundred fifty billion, thirteen million, three hundred fifty-one thousand, seventy-one".
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