12145004245533 has 4 divisors (see below), whose sum is σ = 16193338994048. Its totient is φ = 8096669497020.

The previous prime is 12145004245523. The next prime is 12145004245567. The reversal of 12145004245533 is 33554240054121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12145004245533 - 2¹⁸ = 12145003983389 is a prime.

It is a super-2 number, since 2×12145004245533² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12145004245491 and 12145004245500.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12145004245523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2024167374253 + ... + 2024167374258.

It is an arithmetic number, because the mean of its divisors is an integer number (4048334748512).

Almost surely, 2^{12145004245533} is an apocalyptic number.

It is an amenable number.

12145004245533 is a deficient number, since it is larger than the sum of its proper divisors (4048334748515).

12145004245533 is an equidigital number, since it uses as much as digits as its factorization.

12145004245533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4048334748514.

The product of its (nonzero) digits is 288000, while the sum is 39.

Adding to 12145004245533 its reverse (33554240054121), we get a palindrome (45699244299654).

The spelling of 12145004245533 in words is "twelve trillion, one hundred forty-five billion, four million, two hundred forty-five thousand, five hundred thirty-three".