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12145515153 = 34048505051
BaseRepresentation
bin10110100111110110…
…11101101010010001
31011100102221002121120
423103323131222101
5144333222441103
65325104312453
7606656114112
oct132373355221
934312832546
1012145515153
115172910332
12242b612729
1311b7353275
1483309a209
154b1416253
hex2d3edda91

12145515153 has 4 divisors (see below), whose sum is σ = 16194020208. Its totient is φ = 8097010100.

The previous prime is 12145515127. The next prime is 12145515191. The reversal of 12145515153 is 35151554121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35151554121 = 311717184707.

It is a cyclic number.

It is not a de Polignac number, because 12145515153 - 25 = 12145515121 is a prime.

It is a super-2 number, since 2×121455151532 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12145515553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2024252523 + ... + 2024252528.

It is an arithmetic number, because the mean of its divisors is an integer number (4048505052).

Almost surely, 212145515153 is an apocalyptic number.

It is an amenable number.

12145515153 is a deficient number, since it is larger than the sum of its proper divisors (4048505055).

12145515153 is an equidigital number, since it uses as much as digits as its factorization.

12145515153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4048505054.

The product of its digits is 15000, while the sum is 33.

The spelling of 12145515153 in words is "twelve billion, one hundred forty-five million, five hundred fifteen thousand, one hundred fifty-three".

Divisors: 1 3 4048505051 12145515153