Base | Representation |
---|---|
bin | 111000100100001001… |
… | …1110110011101011001 |
3 | 102121112121110112120212 |
4 | 1301020103312131121 |
5 | 3442233343411031 |
6 | 131445323500505 |
7 | 11530124032403 |
oct | 1611023663531 |
9 | 377477415525 |
10 | 121472247641 |
11 | 47574a0a608 |
12 | 1b660987735 |
13 | b5bb210714 |
14 | 5c44aa3b73 |
15 | 325e36c12b |
hex | 1c484f6759 |
121472247641 has 2 divisors, whose sum is σ = 121472247642. Its totient is φ = 121472247640.
The previous prime is 121472247563. The next prime is 121472247643. The reversal of 121472247641 is 146742274121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97034742016 + 24437505625 = 311504^2 + 156325^2 .
It is a cyclic number.
It is not a de Polignac number, because 121472247641 - 218 = 121471985497 is a prime.
Together with 121472247643, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (121472247643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60736123820 + 60736123821.
It is an arithmetic number, because the mean of its divisors is an integer number (60736123821).
Almost surely, 2121472247641 is an apocalyptic number.
It is an amenable number.
121472247641 is a deficient number, since it is larger than the sum of its proper divisors (1).
121472247641 is an equidigital number, since it uses as much as digits as its factorization.
121472247641 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 150528, while the sum is 41.
The spelling of 121472247641 in words is "one hundred twenty-one billion, four hundred seventy-two million, two hundred forty-seven thousand, six hundred forty-one".
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