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121500330433 is a prime number
BaseRepresentation
bin111000100100111111…
…0111110100111000001
3102121121120022021221021
41301021332332213001
53442313041033213
6131452205425441
711530614524416
oct1611176764701
9377546267837
10121500330433
1147589850629
121b66a26b281
13b5c3c93b61
145c486d410d
153261a67d8d
hex1c49fbe9c1

121500330433 has 2 divisors, whose sum is σ = 121500330434. Its totient is φ = 121500330432.

The previous prime is 121500330431. The next prime is 121500330481. The reversal of 121500330433 is 334033005121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 73779054129 + 47721276304 = 271623^2 + 218452^2 .

It is a cyclic number.

It is not a de Polignac number, because 121500330433 - 21 = 121500330431 is a prime.

Together with 121500330431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 121500330398 and 121500330407.

It is not a weakly prime, because it can be changed into another prime (121500330431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60750165216 + 60750165217.

It is an arithmetic number, because the mean of its divisors is an integer number (60750165217).

Almost surely, 2121500330433 is an apocalyptic number.

It is an amenable number.

121500330433 is a deficient number, since it is larger than the sum of its proper divisors (1).

121500330433 is an equidigital number, since it uses as much as digits as its factorization.

121500330433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 121500330433 its reverse (334033005121), we get a palindrome (455533335554).

The spelling of 121500330433 in words is "one hundred twenty-one billion, five hundred million, three hundred thirty thousand, four hundred thirty-three".