12152025133 has 4 divisors (see below), whose sum is σ = 12158022240. Its totient is φ = 12146028028.

The previous prime is 12152025131. The next prime is 12152025143. The reversal of 12152025133 is 33152025121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33152025121 = 20753 ⋅1597457.

It is a cyclic number.

It is not a de Polignac number, because 12152025133 - 2¹ = 12152025131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12152025098 and 12152025107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12152025131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2995513 + ... + 2999566.

It is an arithmetic number, because the mean of its divisors is an integer number (3039505560).

Almost surely, 2^12152025133 is an apocalyptic number.

It is an amenable number.

12152025133 is a deficient number, since it is larger than the sum of its proper divisors (5997107).

12152025133 is an equidigital number, since it uses as much as digits as its factorization.

12152025133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5997106.

The product of its (nonzero) digits is 1800, while the sum is 25.

The spelling of 12152025133 in words is "twelve billion, one hundred fifty-two million, twenty-five thousand, one hundred thirty-three".