Base | Representation |
---|---|
bin | 1011000011010110111110… |
… | …0001001010001111100111 |
3 | 1121000202022000022212011111 |
4 | 2300311233201022033213 |
5 | 3043100434330202241 |
6 | 41502412132245451 |
7 | 2362656102636502 |
oct | 260655741121747 |
9 | 47022260285144 |
10 | 12152333444071 |
11 | 3965859467027 |
12 | 1443253a70887 |
13 | 6a1c63523982 |
14 | 300267226139 |
15 | 16119b7cac81 |
hex | b0d6f84a3e7 |
12152333444071 has 2 divisors, whose sum is σ = 12152333444072. Its totient is φ = 12152333444070.
The previous prime is 12152333444063. The next prime is 12152333444077. The reversal of 12152333444071 is 17044433325121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12152333444071 - 23 = 12152333444063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12152333444077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6076166722035 + 6076166722036.
It is an arithmetic number, because the mean of its divisors is an integer number (6076166722036).
Almost surely, 212152333444071 is an apocalyptic number.
12152333444071 is a deficient number, since it is larger than the sum of its proper divisors (1).
12152333444071 is an equidigital number, since it uses as much as digits as its factorization.
12152333444071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 12152333444071 its reverse (17044433325121), we get a palindrome (29196766769192).
The spelling of 12152333444071 in words is "twelve trillion, one hundred fifty-two billion, three hundred thirty-three million, four hundred forty-four thousand, seventy-one".
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