Base | Representation |
---|---|
bin | 10001101011110111000… |
… | …011000001011001101001 |
3 | 11022011222010102022022212 |
4 | 101223313003001121221 |
5 | 124402441314320433 |
6 | 2330151324054505 |
7 | 153542620442333 |
oct | 21536703013151 |
9 | 4264863368285 |
10 | 1215325541993 |
11 | 429464648682 |
12 | 177656094435 |
13 | 8a7b2705654 |
14 | 42b71a90453 |
15 | 219303a6d48 |
hex | 11af70c1669 |
1215325541993 has 2 divisors, whose sum is σ = 1215325541994. Its totient is φ = 1215325541992.
The previous prime is 1215325541987. The next prime is 1215325542043. The reversal of 1215325541993 is 3991455235121.
It is an a-pointer prime, because the next prime (1215325542043) can be obtained adding 1215325541993 to its sum of digits (50).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1164128786704 + 51196755289 = 1078948^2 + 226267^2 .
It is a cyclic number.
It is not a de Polignac number, because 1215325541993 - 210 = 1215325540969 is a prime.
It is not a weakly prime, because it can be changed into another prime (1215325541093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607662770996 + 607662770997.
It is an arithmetic number, because the mean of its divisors is an integer number (607662770997).
Almost surely, 21215325541993 is an apocalyptic number.
It is an amenable number.
1215325541993 is a deficient number, since it is larger than the sum of its proper divisors (1).
1215325541993 is an equidigital number, since it uses as much as digits as its factorization.
1215325541993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1458000, while the sum is 50.
The spelling of 1215325541993 in words is "one trillion, two hundred fifteen billion, three hundred twenty-five million, five hundred forty-one thousand, nine hundred ninety-three".
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