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1215401052433 is a prime number
BaseRepresentation
bin10001101011111011100…
…011000100100100010001
311022012011101111122011211
4101223323203010210101
5124403120132134213
62330203022340121
7153544525326361
oct21537343044421
94265141448154
101215401052433
114294a32327a7
1217767742a641
138a7c5253399
1442b7bb089a1
1521936d2053d
hex11afb8c4911

1215401052433 has 2 divisors, whose sum is σ = 1215401052434. Its totient is φ = 1215401052432.

The previous prime is 1215401052431. The next prime is 1215401052449. The reversal of 1215401052433 is 3342501045121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1001704725904 + 213696326529 = 1000852^2 + 462273^2 .

It is a cyclic number.

It is not a de Polignac number, because 1215401052433 - 21 = 1215401052431 is a prime.

Together with 1215401052431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1215401052395 and 1215401052404.

It is not a weakly prime, because it can be changed into another prime (1215401052431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607700526216 + 607700526217.

It is an arithmetic number, because the mean of its divisors is an integer number (607700526217).

Almost surely, 21215401052433 is an apocalyptic number.

It is an amenable number.

1215401052433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1215401052433 is an equidigital number, since it uses as much as digits as its factorization.

1215401052433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1215401052433 its reverse (3342501045121), we get a palindrome (4557902097554).

The spelling of 1215401052433 in words is "one trillion, two hundred fifteen billion, four hundred one million, fifty-two thousand, four hundred thirty-three".