1215512002345 has 4 divisors (see below), whose sum is σ = 1458614402820. Its totient is φ = 972409601872.

The previous prime is 1215512002337. The next prime is 1215512002373. The reversal of 1215512002345 is 5432002155121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 626383605136 + 589128397209 = 791444^2 + 767547^2 .

It is a cyclic number.

It is not a de Polignac number, because 1215512002345 - 2³ = 1215512002337 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121551200230 + ... + 121551200239.

It is an arithmetic number, because the mean of its divisors is an integer number (364653600705).

Almost surely, 2^{1215512002345} is an apocalyptic number.

It is an amenable number.

1215512002345 is a deficient number, since it is larger than the sum of its proper divisors (243102400475).

1215512002345 is an equidigital number, since it uses as much as digits as its factorization.

1215512002345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243102400474.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 1215512002345 its reverse (5432002155121), we get a palindrome (6647514157466).

The spelling of 1215512002345 in words is "one trillion, two hundred fifteen billion, five hundred twelve million, two thousand, three hundred forty-five".