1215531001453 has 4 divisors (see below), whose sum is σ = 1215541613440. Its totient is φ = 1215520389468.

The previous prime is 1215531001439. The next prime is 1215531001459. The reversal of 1215531001453 is 3541001355121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1215531001453 is a prime.

It is a super-2 number, since 2×1215531001453² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1215531001459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5132283 + ... + 5363896.

It is an arithmetic number, because the mean of its divisors is an integer number (303885403360).

Almost surely, 2^{1215531001453} is an apocalyptic number.

It is an amenable number.

1215531001453 is a deficient number, since it is larger than the sum of its proper divisors (10611987).

1215531001453 is a wasteful number, since it uses less digits than its factorization.

1215531001453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10611986.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 1215531001453 its reverse (3541001355121), we get a palindrome (4756532356574).

The spelling of 1215531001453 in words is "one trillion, two hundred fifteen billion, five hundred thirty-one million, one thousand, four hundred fifty-three".