Base | Representation |
---|---|
bin | 10110101001000011… |
… | …00110000100100001 |
3 | 1011101010201221102211 |
4 | 23110201212010201 |
5 | 144343302323243 |
6 | 5330102442121 |
7 | 610140065536 |
oct | 132441460441 |
9 | 34333657384 |
10 | 12155511073 |
11 | 5178518422 |
12 | 2432a33341 |
13 | 11b9443004 |
14 | 83453cd8d |
15 | 4b223cd9d |
hex | 2d4866121 |
12155511073 has 2 divisors, whose sum is σ = 12155511074. Its totient is φ = 12155511072.
The previous prime is 12155511061. The next prime is 12155511097. The reversal of 12155511073 is 37011555121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12155503504 + 7569 = 110252^2 + 87^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12155511073 is a prime.
It is a super-2 number, since 2×121555110732 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12155511013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6077755536 + 6077755537.
It is an arithmetic number, because the mean of its divisors is an integer number (6077755537).
Almost surely, 212155511073 is an apocalyptic number.
It is an amenable number.
12155511073 is a deficient number, since it is larger than the sum of its proper divisors (1).
12155511073 is an equidigital number, since it uses as much as digits as its factorization.
12155511073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5250, while the sum is 31.
The spelling of 12155511073 in words is "twelve billion, one hundred fifty-five million, five hundred eleven thousand, seventy-three".
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