Base | Representation |
---|---|
bin | 111000100110111011… |
… | …0101000000111011101 |
3 | 102121210002110112212011 |
4 | 1301031312220013131 |
5 | 3442431201000023 |
6 | 131502445111221 |
7 | 11532333401344 |
oct | 1611566500735 |
9 | 377702415764 |
10 | 121565250013 |
11 | 47612461679 |
12 | 1b687b58511 |
13 | b6045740cc |
14 | 5c53192b5b |
15 | 32675dd50d |
hex | 1c4dda81dd |
121565250013 has 2 divisors, whose sum is σ = 121565250014. Its totient is φ = 121565250012.
The previous prime is 121565249999. The next prime is 121565250029. The reversal of 121565250013 is 310052565121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110142343129 + 11422906884 = 331877^2 + 106878^2 .
It is a cyclic number.
It is not a de Polignac number, because 121565250013 - 29 = 121565249501 is a prime.
It is a super-2 number, since 2×1215652500132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121565250113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60782625006 + 60782625007.
It is an arithmetic number, because the mean of its divisors is an integer number (60782625007).
Almost surely, 2121565250013 is an apocalyptic number.
It is an amenable number.
121565250013 is a deficient number, since it is larger than the sum of its proper divisors (1).
121565250013 is an equidigital number, since it uses as much as digits as its factorization.
121565250013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 121565250013 in words is "one hundred twenty-one billion, five hundred sixty-five million, two hundred fifty thousand, thirteen".
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