Base | Representation |
---|---|
bin | 10001101100100111000… |
… | …011100000010111000101 |
3 | 11022021001020222112221101 |
4 | 101230213003200113011 |
5 | 124411114012201143 |
6 | 2330403255220101 |
7 | 153601600505122 |
oct | 21544703402705 |
9 | 4267036875841 |
10 | 1216130975173 |
11 | 42983825a534 |
12 | 17783b977631 |
13 | 8a8b053b52a |
14 | 42c0aa31749 |
15 | 2197ae53b4d |
hex | 11b270e05c5 |
1216130975173 has 2 divisors, whose sum is σ = 1216130975174. Its totient is φ = 1216130975172.
The previous prime is 1216130975119. The next prime is 1216130975197. The reversal of 1216130975173 is 3715790316121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1100352746529 + 115778228644 = 1048977^2 + 340262^2 .
It is a cyclic number.
It is not a de Polignac number, because 1216130975173 - 233 = 1207541040581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1216130975473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 608065487586 + 608065487587.
It is an arithmetic number, because the mean of its divisors is an integer number (608065487587).
Almost surely, 21216130975173 is an apocalyptic number.
It is an amenable number.
1216130975173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1216130975173 is an equidigital number, since it uses as much as digits as its factorization.
1216130975173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 238140, while the sum is 46.
The spelling of 1216130975173 in words is "one trillion, two hundred sixteen billion, one hundred thirty million, nine hundred seventy-five thousand, one hundred seventy-three".
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