Base | Representation |
---|---|
bin | 111000101001001000… |
… | …1011011011001111111 |
3 | 102121222020221222112102 |
4 | 1301102101123121333 |
5 | 3443104140302303 |
6 | 131514054055315 |
7 | 11534223465434 |
oct | 1612221333177 |
9 | 377866858472 |
10 | 121639384703 |
11 | 47650297111 |
12 | 1b6a894a53b |
13 | b616a2c8a5 |
14 | 5c5cd6db8b |
15 | 326dd84288 |
hex | 1c5245b67f |
121639384703 has 4 divisors (see below), whose sum is σ = 121648164120. Its totient is φ = 121630605288.
The previous prime is 121639384687. The next prime is 121639384753. The reversal of 121639384703 is 307483936121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 121639384703 - 24 = 121639384687 is a prime.
It is a super-2 number, since 2×1216393847032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121639384753) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4368893 + ... + 4396646.
It is an arithmetic number, because the mean of its divisors is an integer number (30412041030).
Almost surely, 2121639384703 is an apocalyptic number.
121639384703 is a deficient number, since it is larger than the sum of its proper divisors (8779417).
121639384703 is an equidigital number, since it uses as much as digits as its factorization.
121639384703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8779416.
The product of its (nonzero) digits is 653184, while the sum is 47.
The spelling of 121639384703 in words is "one hundred twenty-one billion, six hundred thirty-nine million, three hundred eighty-four thousand, seven hundred three".
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