Base | Representation |
---|---|
bin | 10001101100111001110… |
… | …110110110100101000101 |
3 | 11022021212020120002022121 |
4 | 101230321312312211011 |
5 | 124412240241103123 |
6 | 2330454444325541 |
7 | 153612451004122 |
oct | 21547166664505 |
9 | 4267766502277 |
10 | 1216446425413 |
11 | 42998a326a0a |
12 | 1779095438b1 |
13 | 8a9309b888b |
14 | 42c3a8a7749 |
15 | 219989b575d |
hex | 11b39db6945 |
1216446425413 has 2 divisors, whose sum is σ = 1216446425414. Its totient is φ = 1216446425412.
The previous prime is 1216446425393. The next prime is 1216446425461. The reversal of 1216446425413 is 3145246446121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1039009185124 + 177437240289 = 1019318^2 + 421233^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1216446425413 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1216446425413.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1216446495413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 608223212706 + 608223212707.
It is an arithmetic number, because the mean of its divisors is an integer number (608223212707).
Almost surely, 21216446425413 is an apocalyptic number.
It is an amenable number.
1216446425413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1216446425413 is an equidigital number, since it uses as much as digits as its factorization.
1216446425413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 552960, while the sum is 43.
The spelling of 1216446425413 in words is "one trillion, two hundred sixteen billion, four hundred forty-six million, four hundred twenty-five thousand, four hundred thirteen".
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