Base | Representation |
---|---|
bin | 10001101101000000001… |
… | …110101011010101100001 |
3 | 11022022010200201121111002 |
4 | 101231000032223111201 |
5 | 124413000123142423 |
6 | 2330513224001345 |
7 | 153615216502235 |
oct | 21550016532541 |
9 | 4268120647432 |
10 | 1216553334113 |
11 | 429a34707007 |
12 | 177939300255 |
13 | 8a949baab70 |
14 | 42c4ab765c5 |
15 | 219a3082228 |
hex | 11b403ab561 |
1216553334113 has 8 divisors (see below), whose sum is σ = 1310143328256. Its totient is φ = 1122964621200.
The previous prime is 1216553334089. The next prime is 1216553334119. The reversal of 1216553334113 is 3114333556121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1216553334113 - 26 = 1216553334049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1216553334119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2722208 + ... + 3137438.
It is an arithmetic number, because the mean of its divisors is an integer number (163767916032).
Almost surely, 21216553334113 is an apocalyptic number.
1216553334113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1216553334113 is a deficient number, since it is larger than the sum of its proper divisors (93589994143).
1216553334113 is a wasteful number, since it uses less digits than its factorization.
1216553334113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 640615.
The product of its digits is 97200, while the sum is 38.
The spelling of 1216553334113 in words is "one trillion, two hundred sixteen billion, five hundred fifty-three million, three hundred thirty-four thousand, one hundred thirteen".
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