Base | Representation |
---|---|
bin | 10110101010010110… |
… | …01001010110101001 |
3 | 1011101220020100000221 |
4 | 23111023021112221 |
5 | 144404044402442 |
6 | 5331132130041 |
7 | 610331503063 |
oct | 132513112651 |
9 | 34356210027 |
10 | 12166403497 |
11 | 5183688026 |
12 | 2436606921 |
13 | 11bb787b31 |
14 | 835b76733 |
15 | 4b3190467 |
hex | 2d52c95a9 |
12166403497 has 2 divisors, whose sum is σ = 12166403498. Its totient is φ = 12166403496.
The previous prime is 12166403489. The next prime is 12166403563. The reversal of 12166403497 is 79430466121.
12166403497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9996800256 + 2169603241 = 99984^2 + 46579^2 .
It is a cyclic number.
It is not a de Polignac number, because 12166403497 - 23 = 12166403489 is a prime.
It is not a weakly prime, because it can be changed into another prime (12166403297) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6083201748 + 6083201749.
It is an arithmetic number, because the mean of its divisors is an integer number (6083201749).
Almost surely, 212166403497 is an apocalyptic number.
It is an amenable number.
12166403497 is a deficient number, since it is larger than the sum of its proper divisors (1).
12166403497 is an equidigital number, since it uses as much as digits as its factorization.
12166403497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 43.
The spelling of 12166403497 in words is "twelve billion, one hundred sixty-six million, four hundred three thousand, four hundred ninety-seven".
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