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12170000053 = 17659689167
BaseRepresentation
bin10110101010110001…
…10111011010110101
31011102011000001120201
423111120313122311
5144411010000203
65331341200501
7610404202501
oct132530673265
934364001521
1012170000053
115185714192
122437860131
1311bc446b83
14836431301
154b3650e1d
hex2d56376b5

12170000053 has 4 divisors (see below), whose sum is σ = 12170706880. Its totient is φ = 12169293228.

The previous prime is 12170000047. The next prime is 12170000071. The reversal of 12170000053 is 35000007121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12170000053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12170300053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326925 + ... + 362242.

It is an arithmetic number, because the mean of its divisors is an integer number (3042676720).

Almost surely, 212170000053 is an apocalyptic number.

It is an amenable number.

12170000053 is a deficient number, since it is larger than the sum of its proper divisors (706827).

12170000053 is an equidigital number, since it uses as much as digits as its factorization.

12170000053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 706826.

The product of its (nonzero) digits is 210, while the sum is 19.

Adding to 12170000053 its reverse (35000007121), we get a palindrome (47170007174).

The spelling of 12170000053 in words is "twelve billion, one hundred seventy million, fifty-three", and thus it is an aban number.

Divisors: 1 17659 689167 12170000053