Base | Representation |
---|---|
bin | 10110101010111000… |
… | …10100111111111001 |
3 | 1011102012201011120002 |
4 | 23111130110333321 |
5 | 144411223021031 |
6 | 5331412442345 |
7 | 610415002514 |
oct | 132534247771 |
9 | 34365634502 |
10 | 12170907641 |
11 | 5186184062 |
12 | 24380193b5 |
13 | 11bc6a3cc9 |
14 | 8365c9d7b |
15 | 4b377eccb |
hex | 2d5714ff9 |
12170907641 has 2 divisors, whose sum is σ = 12170907642. Its totient is φ = 12170907640.
The previous prime is 12170907599. The next prime is 12170907643. The reversal of 12170907641 is 14670907121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10159833616 + 2011074025 = 100796^2 + 44845^2 .
It is a cyclic number.
It is not a de Polignac number, because 12170907641 - 218 = 12170645497 is a prime.
Together with 12170907643, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12170907595 and 12170907604.
It is not a weakly prime, because it can be changed into another prime (12170907643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6085453820 + 6085453821.
It is an arithmetic number, because the mean of its divisors is an integer number (6085453821).
Almost surely, 212170907641 is an apocalyptic number.
It is an amenable number.
12170907641 is a deficient number, since it is larger than the sum of its proper divisors (1).
12170907641 is an equidigital number, since it uses as much as digits as its factorization.
12170907641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21168, while the sum is 38.
The spelling of 12170907641 in words is "twelve billion, one hundred seventy million, nine hundred seven thousand, six hundred forty-one".
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