Base | Representation |
---|---|
bin | 1011000100100000011000… |
… | …1000010011010010011001 |
3 | 1121002122011101222120020200 |
4 | 2301020012020103102121 |
5 | 3043411314240000223 |
6 | 41515431423412413 |
7 | 2364254334141162 |
oct | 261100610232231 |
9 | 47078141876220 |
10 | 12172040156313 |
11 | 3973151386674 |
12 | 1447033754109 |
13 | 6a3a84210a4b |
14 | 3011b65a4769 |
15 | 161951911a43 |
hex | b1206213499 |
12172040156313 has 24 divisors (see below), whose sum is σ = 18620088272448. Its totient is φ = 7646031705312.
The previous prime is 12172040156291. The next prime is 12172040156399. The reversal of 12172040156313 is 31365104027121.
12172040156313 is a `hidden beast` number, since 1 + 2 + 1 + 7 + 2 + 0 + 4 + 0 + 15 + 631 + 3 = 666.
It is a de Polignac number, because none of the positive numbers 2k-12172040156313 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12172040156413) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 438807970 + ... + 438835707.
It is an arithmetic number, because the mean of its divisors is an integer number (775837011352).
Almost surely, 212172040156313 is an apocalyptic number.
It is an amenable number.
12172040156313 is a deficient number, since it is larger than the sum of its proper divisors (6448048116135).
12172040156313 is a wasteful number, since it uses less digits than its factorization.
12172040156313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 877643773 (or 877643770 counting only the distinct ones).
The product of its (nonzero) digits is 30240, while the sum is 36.
The spelling of 12172040156313 in words is "twelve trillion, one hundred seventy-two billion, forty million, one hundred fifty-six thousand, three hundred thirteen".
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