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121756525481 is a prime number
BaseRepresentation
bin111000101100101000…
…0010010001110101001
3102122021102101100110202
41301121100102032221
53443324132303411
6131533440521545
711540145250643
oct1613120221651
9378242340422
10121756525481
1147700425778
121b7200202b5
13b635095266
145c70743893
1532792c283b
hex1c594123a9

121756525481 has 2 divisors, whose sum is σ = 121756525482. Its totient is φ = 121756525480.

The previous prime is 121756525441. The next prime is 121756525483. The reversal of 121756525481 is 184525657121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100399625881 + 21356899600 = 316859^2 + 146140^2 .

It is a cyclic number.

It is not a de Polignac number, because 121756525481 - 222 = 121752331177 is a prime.

It is a super-2 number, since 2×1217565254812 (a number of 23 digits) contains 22 as substring.

Together with 121756525483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (121756525483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60878262740 + 60878262741.

It is an arithmetic number, because the mean of its divisors is an integer number (60878262741).

Almost surely, 2121756525481 is an apocalyptic number.

It is an amenable number.

121756525481 is a deficient number, since it is larger than the sum of its proper divisors (1).

121756525481 is an equidigital number, since it uses as much as digits as its factorization.

121756525481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 672000, while the sum is 47.

The spelling of 121756525481 in words is "one hundred twenty-one billion, seven hundred fifty-six million, five hundred twenty-five thousand, four hundred eighty-one".