Search a number
-
+
121786365490567 is a prime number
BaseRepresentation
bin11011101100001110011001…
…000011011011010110000111
3120222012122220012121100122021
4123230032121003123112013
5111430321434031144232
61111003514532544011
734436526445261651
oct3354163103332607
9528178805540567
10121786365490567
11358943423a0088
12117ab01b482007
1352c55359b0bcb
1422106c4b056d1
15e12e221c4397
hex6ec3990db587

121786365490567 has 2 divisors, whose sum is σ = 121786365490568. Its totient is φ = 121786365490566.

The previous prime is 121786365490553. The next prime is 121786365490597. The reversal of 121786365490567 is 765094563687121.

It is a weak prime.

It is an emirp because it is prime and its reverse (765094563687121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121786365490567 - 211 = 121786365488519 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121786365490496 and 121786365490505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121786365490597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60893182745283 + 60893182745284.

It is an arithmetic number, because the mean of its divisors is an integer number (60893182745284).

It is a 1-persistent number, because it is pandigital, but 2⋅121786365490567 = 243572730981134 is not.

Almost surely, 2121786365490567 is an apocalyptic number.

121786365490567 is a deficient number, since it is larger than the sum of its proper divisors (1).

121786365490567 is an equidigital number, since it uses as much as digits as its factorization.

121786365490567 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 457228800, while the sum is 70.

The spelling of 121786365490567 in words is "one hundred twenty-one trillion, seven hundred eighty-six billion, three hundred sixty-five million, four hundred ninety thousand, five hundred sixty-seven".