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121813392131 is a prime number
BaseRepresentation
bin111000101110010100…
…1001101101100000011
3102122102101101110211222
41301130221031230003
53443433212022011
6131543231425255
711541435514634
oct1613451155403
9378371343758
10121813392131
114772a536502
121b73708522b
13b643ab5c72
145c7810788b
15327e2a6ddb
hex1c5ca4db03

121813392131 has 2 divisors, whose sum is σ = 121813392132. Its totient is φ = 121813392130.

The previous prime is 121813392083. The next prime is 121813392133. The reversal of 121813392131 is 131293318121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121813392131 is a prime.

It is a super-2 number, since 2×1218133921312 (a number of 23 digits) contains 22 as substring.

Together with 121813392133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121813392091 and 121813392100.

It is not a weakly prime, because it can be changed into another prime (121813392133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60906696065 + 60906696066.

It is an arithmetic number, because the mean of its divisors is an integer number (60906696066).

Almost surely, 2121813392131 is an apocalyptic number.

121813392131 is a deficient number, since it is larger than the sum of its proper divisors (1).

121813392131 is an equidigital number, since it uses as much as digits as its factorization.

121813392131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7776, while the sum is 35.

The spelling of 121813392131 in words is "one hundred twenty-one billion, eight hundred thirteen million, three hundred ninety-two thousand, one hundred thirty-one".