Base | Representation |
---|---|
bin | 10110101100001110… |
… | …00101110111001011 |
3 | 1011102222210201001110 |
4 | 23112013011313023 |
5 | 144422110232320 |
6 | 5332453021403 |
7 | 610612202346 |
oct | 132607056713 |
9 | 34388721043 |
10 | 12182117835 |
11 | 5191540488 |
12 | 243b924863 |
13 | 11c1aca664 |
14 | 837ca745d |
15 | 4b47465e0 |
hex | 2d61c5dcb |
12182117835 has 8 divisors (see below), whose sum is σ = 19491388560. Its totient is φ = 6497129504.
The previous prime is 12182117821. The next prime is 12182117851. The reversal of 12182117835 is 53871128121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12182117835 - 25 = 12182117803 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12182117793 and 12182117802.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 406070580 + ... + 406070609.
It is an arithmetic number, because the mean of its divisors is an integer number (2436423570).
Almost surely, 212182117835 is an apocalyptic number.
12182117835 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12182117835 is a deficient number, since it is larger than the sum of its proper divisors (7309270725).
12182117835 is an equidigital number, since it uses as much as digits as its factorization.
12182117835 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 812141197.
The product of its digits is 26880, while the sum is 39.
It can be divided in two parts, 121821 and 17835, that added together give a triangular number (139656 = T528).
The spelling of 12182117835 in words is "twelve billion, one hundred eighty-two million, one hundred seventeen thousand, eight hundred thirty-five".
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