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1218214550857 is a prime number
BaseRepresentation
bin10001101110100011001…
…111101101110101001001
311022110102110121011110011
4101232203033231311021
5124424400411111412
62331350125351521
7154004330554603
oct21564317556511
94273373534404
101218214550857
1142a70739a807
121781217085a1
138ab530c8655
1442d67644173
1521a4dd247a7
hex11ba33edd49

1218214550857 has 2 divisors, whose sum is σ = 1218214550858. Its totient is φ = 1218214550856.

The previous prime is 1218214550849. The next prime is 1218214550899. The reversal of 1218214550857 is 7580554128121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1030013890816 + 188200660041 = 1014896^2 + 433821^2 .

It is a cyclic number.

It is not a de Polignac number, because 1218214550857 - 23 = 1218214550849 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1218214550857.

It is not a weakly prime, because it can be changed into another prime (1218214556857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 609107275428 + 609107275429.

It is an arithmetic number, because the mean of its divisors is an integer number (609107275429).

Almost surely, 21218214550857 is an apocalyptic number.

It is an amenable number.

1218214550857 is a deficient number, since it is larger than the sum of its proper divisors (1).

1218214550857 is an equidigital number, since it uses as much as digits as its factorization.

1218214550857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 896000, while the sum is 49.

Adding to 1218214550857 its reverse (7580554128121), we get a palindrome (8798768678978).

The spelling of 1218214550857 in words is "one trillion, two hundred eighteen billion, two hundred fourteen million, five hundred fifty thousand, eight hundred fifty-seven".