Base | Representation |
---|---|
bin | 10110101100011111… |
… | …10100001101100110 |
3 | 1011110011002220020021 |
4 | 23112033310031212 |
5 | 144423201423323 |
6 | 5333014025354 |
7 | 610640506114 |
oct | 132617641546 |
9 | 34404086207 |
10 | 12184404838 |
11 | 5192862771 |
12 | 244064825a |
13 | 11c241b608 |
14 | 838300ab4 |
15 | 4b4a4905d |
hex | 2d63f4366 |
12184404838 has 4 divisors (see below), whose sum is σ = 18276607260. Its totient is φ = 6092202418.
The previous prime is 12184404829. The next prime is 12184404847. The reversal of 12184404838 is 83840448121.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (12184404829) and next prime (12184404847).
It is a junction number, because it is equal to n+sod(n) for n = 12184404794 and 12184404803.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3046101208 + ... + 3046101211.
It is an arithmetic number, because the mean of its divisors is an integer number (4569151815).
Almost surely, 212184404838 is an apocalyptic number.
12184404838 is a deficient number, since it is larger than the sum of its proper divisors (6092202422).
12184404838 is an equidigital number, since it uses as much as digits as its factorization.
12184404838 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6092202421.
The product of its (nonzero) digits is 196608, while the sum is 43.
The spelling of 12184404838 in words is "twelve billion, one hundred eighty-four million, four hundred four thousand, eight hundred thirty-eight".
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