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12200020121122 = 26100010060561
BaseRepresentation
bin1011000110001000100111…
…0111011001011000100010
31121012022101101020001021121
42301202021313121120202
53044341120122333442
641540340055242454
72366264605001461
oct261421167313042
947168341201247
1012200020121122
113983aaa339329
12145054207942a
136a65c2c35342
143026ac61a9d8
1516253d01b967
hexb1889dd9622

12200020121122 has 4 divisors (see below), whose sum is σ = 18300030181686. Its totient is φ = 6100010060560.

The previous prime is 12200020121101. The next prime is 12200020121137. The reversal of 12200020121122 is 22112102000221.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10727780058241 + 1472240062881 = 3275329^2 + 1213359^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12200020121096 and 12200020121105.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3050005030279 + ... + 3050005030282.

Almost surely, 212200020121122 is an apocalyptic number.

12200020121122 is a deficient number, since it is larger than the sum of its proper divisors (6100010060564).

12200020121122 is an equidigital number, since it uses as much as digits as its factorization.

12200020121122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6100010060563.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 12200020121122 its reverse (22112102000221), we get a palindrome (34312122121343).

The spelling of 12200020121122 in words is "twelve trillion, two hundred billion, twenty million, one hundred twenty-one thousand, one hundred twenty-two".

Divisors: 1 2 6100010060561 12200020121122