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12200033120993 is a prime number
BaseRepresentation
bin1011000110001000101010…
…1000111111001011100001
31121012022102021200111202022
42301202022220333023201
53044341131434332433
641540341242031225
72366265123334124
oct261421250771341
947168367614668
1012200033120993
113984006708323
1214505464a8515
136a65c5837483
143026b02423bb
1516253e238698
hexb188aa3f2e1

12200033120993 has 2 divisors, whose sum is σ = 12200033120994. Its totient is φ = 12200033120992.

The previous prime is 12200033120939. The next prime is 12200033121037. The reversal of 12200033120993 is 39902133000221.

It is a happy number.

Together with previous prime (12200033120939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9319300879009 + 2880732241984 = 3052753^2 + 1697272^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12200033120993 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12200035120993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100016560496 + 6100016560497.

It is an arithmetic number, because the mean of its divisors is an integer number (6100016560497).

Almost surely, 212200033120993 is an apocalyptic number.

It is an amenable number.

12200033120993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12200033120993 is an equidigital number, since it uses as much as digits as its factorization.

12200033120993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 35.

The spelling of 12200033120993 in words is "twelve trillion, two hundred billion, thirty-three million, one hundred twenty thousand, nine hundred ninety-three".