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122001330211102 = 261000665105551
BaseRepresentation
bin11011101111010110100101…
…111100110000100100011110
3120222222012202110122121111101
4123233112211330300210132
5111442332211013223402
61111250345400543314
734461206460250546
oct3357264574604436
9528865673577441
10122001330211102
1135967523377311
1211824812781b3a
13530c8a34460b4
14221ac78466326
15e188042deb87
hex6ef5a5f3091e

122001330211102 has 4 divisors (see below), whose sum is σ = 183001995316656. Its totient is φ = 61000665105550.

The previous prime is 122001330211097. The next prime is 122001330211109. The reversal of 122001330211102 is 201112033100221.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 122001330211102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122001330211109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30500332552774 + ... + 30500332552777.

It is an arithmetic number, because the mean of its divisors is an integer number (45750498829164).

Almost surely, 2122001330211102 is an apocalyptic number.

122001330211102 is a deficient number, since it is larger than the sum of its proper divisors (61000665105554).

122001330211102 is an equidigital number, since it uses as much as digits as its factorization.

122001330211102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61000665105553.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 122001330211102 its reverse (201112033100221), we get a palindrome (323113363311323).

The spelling of 122001330211102 in words is "one hundred twenty-two trillion, one billion, three hundred thirty million, two hundred eleven thousand, one hundred two".

Divisors: 1 2 61000665105551 122001330211102