Base | Representation |
---|---|
bin | 10001110000010011110… |
… | …100000111101111001111 |
3 | 11022122022002022112221021 |
4 | 101300103310013233033 |
5 | 124442232401023401 |
6 | 2332301352415011 |
7 | 154102202410342 |
oct | 21602364075717 |
9 | 4278262275837 |
10 | 1220103142351 |
11 | 430496463525 |
12 | 17856a0a7467 |
13 | 8b094466502 |
14 | 430a63bc459 |
15 | 21b0ea2c2a1 |
hex | 11c13d07bcf |
1220103142351 has 2 divisors, whose sum is σ = 1220103142352. Its totient is φ = 1220103142350.
The previous prime is 1220103142337. The next prime is 1220103142417. The reversal of 1220103142351 is 1532413010221.
It is a weak prime.
It is an emirp because it is prime and its reverse (1532413010221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1220103142351 - 221 = 1220101045199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1220103142151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610051571175 + 610051571176.
It is an arithmetic number, because the mean of its divisors is an integer number (610051571176).
Almost surely, 21220103142351 is an apocalyptic number.
1220103142351 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220103142351 is an equidigital number, since it uses as much as digits as its factorization.
1220103142351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1220103142351 its reverse (1532413010221), we get a palindrome (2752516152572).
The spelling of 1220103142351 in words is "one trillion, two hundred twenty billion, one hundred three million, one hundred forty-two thousand, three hundred fifty-one".
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