Base | Representation |
---|---|
bin | 11011101111011111101000… |
… | …000111010111100100011101 |
3 | 121000000010210110221021111020 |
4 | 123233133220013113210131 |
5 | 111443012042214120013 |
6 | 1111255032105514353 |
7 | 34462002033063162 |
oct | 3357375007274435 |
9 | 530003713837436 |
10 | 122011030223133 |
11 | 35970650815987 |
12 | 1182667b1a29b9 |
13 | 531078ac3b09c |
14 | 221b51881a069 |
15 | e18bc0b92623 |
hex | 6ef7e81d791d |
122011030223133 has 4 divisors (see below), whose sum is σ = 162681373630848. Its totient is φ = 81340686815420.
The previous prime is 122011030223129. The next prime is 122011030223167. The reversal of 122011030223133 is 331322030110221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 122011030223133 - 22 = 122011030223129 is a prime.
It is a super-2 number, since 2×1220110302231332 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122011030223183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20335171703853 + ... + 20335171703858.
It is an arithmetic number, because the mean of its divisors is an integer number (40670343407712).
Almost surely, 2122011030223133 is an apocalyptic number.
It is an amenable number.
122011030223133 is a deficient number, since it is larger than the sum of its proper divisors (40670343407715).
122011030223133 is an equidigital number, since it uses as much as digits as its factorization.
122011030223133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40670343407714.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 122011030223133 its reverse (331322030110221), we get a palindrome (453333060333354).
The spelling of 122011030223133 in words is "one hundred twenty-two trillion, eleven billion, thirty million, two hundred twenty-three thousand, one hundred thirty-three".
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