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12201110021143 is a prime number
BaseRepresentation
bin1011000110001100101011…
…0101000010010000010111
31121012102012100001201001001
42301203022311002100113
53044400333131134033
641541040151444131
72366333611000531
oct261431265022027
947172170051031
1012201110021143
11398450958534a
1214507a7086647
136a673798aab4
1430277328a851
151625a3a59e7d
hexb18cad42417

12201110021143 has 2 divisors, whose sum is σ = 12201110021144. Its totient is φ = 12201110021142.

The previous prime is 12201110021101. The next prime is 12201110021227. The reversal of 12201110021143 is 34112001110221.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12201110021143 is a prime.

It is a super-2 number, since 2×122011100211432 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12201110021143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12201110028143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100555010571 + 6100555010572.

It is an arithmetic number, because the mean of its divisors is an integer number (6100555010572).

Almost surely, 212201110021143 is an apocalyptic number.

12201110021143 is a deficient number, since it is larger than the sum of its proper divisors (1).

12201110021143 is an equidigital number, since it uses as much as digits as its factorization.

12201110021143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 12201110021143 its reverse (34112001110221), we get a palindrome (46313111131364).

The spelling of 12201110021143 in words is "twelve trillion, two hundred one billion, one hundred ten million, twenty-one thousand, one hundred forty-three".