Base | Representation |
---|---|
bin | 1011000110001100101101… |
… | …1011100010000010110111 |
3 | 1121012102020001001102012222 |
4 | 2301203023123202002313 |
5 | 3044400343222102243 |
6 | 41541041152032555 |
7 | 2366334062531405 |
oct | 261431333420267 |
9 | 47172201042188 |
10 | 12201120112823 |
11 | 3984514248384 |
12 | 14507aa53275b |
13 | 6a6739ab22c5 |
14 | 302774756475 |
15 | 1625a48a0168 |
hex | b18cb6e20b7 |
12201120112823 has 2 divisors, whose sum is σ = 12201120112824. Its totient is φ = 12201120112822.
The previous prime is 12201120112801. The next prime is 12201120112871. The reversal of 12201120112823 is 32821102110221.
12201120112823 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12201120112823 - 216 = 12201120047287 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12201120112792 and 12201120112801.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12201120162823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100560056411 + 6100560056412.
It is an arithmetic number, because the mean of its divisors is an integer number (6100560056412).
Almost surely, 212201120112823 is an apocalyptic number.
12201120112823 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201120112823 is an equidigital number, since it uses as much as digits as its factorization.
12201120112823 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 26.
The spelling of 12201120112823 in words is "twelve trillion, two hundred one billion, one hundred twenty million, one hundred twelve thousand, eight hundred twenty-three".
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