Base | Representation |
---|---|
bin | 10001110000010100011… |
… | …110000101010011110011 |
3 | 11022122022212000102020101 |
4 | 101300110132011103303 |
5 | 124442243210024301 |
6 | 2332302424253231 |
7 | 154102365043531 |
oct | 21602436052363 |
9 | 4278285012211 |
10 | 1220114142451 |
11 | 4304a1697016 |
12 | 178571911217 |
13 | 8b096818349 |
14 | 430a7a43151 |
15 | 21b109a1701 |
hex | 11c147854f3 |
1220114142451 has 2 divisors, whose sum is σ = 1220114142452. Its totient is φ = 1220114142450.
The previous prime is 1220114142449. The next prime is 1220114142469. The reversal of 1220114142451 is 1542414110221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1220114142451 - 21 = 1220114142449 is a prime.
Together with 1220114142449, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1220114142251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610057071225 + 610057071226.
It is an arithmetic number, because the mean of its divisors is an integer number (610057071226).
Almost surely, 21220114142451 is an apocalyptic number.
1220114142451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220114142451 is an equidigital number, since it uses as much as digits as its factorization.
1220114142451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 28.
Adding to 1220114142451 its reverse (1542414110221), we get a palindrome (2762528252672).
The spelling of 1220114142451 in words is "one trillion, two hundred twenty billion, one hundred fourteen million, one hundred forty-two thousand, four hundred fifty-one".
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