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1220120202111 = 3406706734037
BaseRepresentation
bin10001110000010100110…
…101001100101101111111
311022122100021102021112020
4101300110311030231333
5124442301232431421
62332303202211223
7154102500412266
oct21602465145577
94278307367466
101220120202111
114304a50557a8
12178573953b13
138b097b5a545
14430a877d5dd
1521b1129bdc6
hex11c14d4cb7f

1220120202111 has 4 divisors (see below), whose sum is σ = 1626826936152. Its totient is φ = 813413468072.

The previous prime is 1220120202031. The next prime is 1220120202139. The reversal of 1220120202111 is 1112020210221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1220120202111 - 215 = 1220120169343 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1220120202181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203353367016 + ... + 203353367021.

It is an arithmetic number, because the mean of its divisors is an integer number (406706734038).

Almost surely, 21220120202111 is an apocalyptic number.

1220120202111 is a deficient number, since it is larger than the sum of its proper divisors (406706734041).

1220120202111 is an equidigital number, since it uses as much as digits as its factorization.

1220120202111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 406706734040.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 1220120202111 its reverse (1112020210221), we get a palindrome (2332140412332).

The spelling of 1220120202111 in words is "one trillion, two hundred twenty billion, one hundred twenty million, two hundred two thousand, one hundred eleven".

Divisors: 1 3 406706734037 1220120202111