Base | Representation |
---|---|
bin | 11011101111100000100011… |
… | …000111111000000100101011 |
3 | 121000000020100110202220220222 |
4 | 123233200203013320010223 |
5 | 111443021104133241021 |
6 | 1111255314232440255 |
7 | 34462035413620136 |
oct | 3357404307700453 |
9 | 530006313686828 |
10 | 122012020212011 |
11 | 35971009621206 |
12 | 118268b684908b |
13 | 53108b8081617 |
14 | 221b5b00bd21d |
15 | e18c2ca476ab |
hex | 6ef8231f812b |
122012020212011 has 4 divisors (see below), whose sum is σ = 122013212991024. Its totient is φ = 122010827433000.
The previous prime is 122012020212001. The next prime is 122012020212013. The reversal of 122012020212011 is 110212020210221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 122012020212011 - 214 = 122012020195627 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (122012020212013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596236055 + ... + 596440656.
It is an arithmetic number, because the mean of its divisors is an integer number (30503303247756).
Almost surely, 2122012020212011 is an apocalyptic number.
122012020212011 is a deficient number, since it is larger than the sum of its proper divisors (1192779013).
122012020212011 is a wasteful number, since it uses less digits than its factorization.
122012020212011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1192779012.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 122012020212011 its reverse (110212020210221), we get a palindrome (232224040422232).
The spelling of 122012020212011 in words is "one hundred twenty-two trillion, twelve billion, twenty million, two hundred twelve thousand, eleven".
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