Base | Representation |
---|---|
bin | 10001110000010100111… |
… | …000101100110111011111 |
3 | 11022122100100010220221101 |
4 | 101300110320230313133 |
5 | 124442302001321343 |
6 | 2332303234013531 |
7 | 154102511255065 |
oct | 21602470546737 |
9 | 4278310126841 |
10 | 1220121120223 |
11 | 4304a5622575 |
12 | 1785741172a7 |
13 | 8b0980bc3c5 |
14 | 430a893c035 |
15 | 21b113cde4d |
hex | 11c14e2cddf |
1220121120223 has 2 divisors, whose sum is σ = 1220121120224. Its totient is φ = 1220121120222.
The previous prime is 1220121120191. The next prime is 1220121120247. The reversal of 1220121120223 is 3220211210221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220121120223 - 25 = 1220121120191 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1220121120223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1220121120293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610060560111 + 610060560112.
It is an arithmetic number, because the mean of its divisors is an integer number (610060560112).
Almost surely, 21220121120223 is an apocalyptic number.
1220121120223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220121120223 is an equidigital number, since it uses as much as digits as its factorization.
1220121120223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 1220121120223 its reverse (3220211210221), we get a palindrome (4440332330444).
The spelling of 1220121120223 in words is "one trillion, two hundred twenty billion, one hundred twenty-one million, one hundred twenty thousand, two hundred twenty-three".
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