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12201222110993 is a prime number
BaseRepresentation
bin1011000110001101000110…
…0000100111111100010001
31121012102111010222110101222
42301203101200213330101
53044401100330022433
641541055234134425
72366336441515226
oct261432140477421
947172433873358
1012201222110993
113984566884093
121450818721415
136a6754c75456
1430278410794d
151625ad7ebb98
hexb18d1827f11

12201222110993 has 2 divisors, whose sum is σ = 12201222110994. Its totient is φ = 12201222110992.

The previous prime is 12201222110983. The next prime is 12201222111011. The reversal of 12201222110993 is 39901122210221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11866702156864 + 334519954129 = 3444808^2 + 578377^2 .

It is a cyclic number.

It is not a de Polignac number, because 12201222110993 - 214 = 12201222094609 is a prime.

It is a super-2 number, since 2×122012221109932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12201222110923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100611055496 + 6100611055497.

It is an arithmetic number, because the mean of its divisors is an integer number (6100611055497).

Almost surely, 212201222110993 is an apocalyptic number.

It is an amenable number.

12201222110993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12201222110993 is an equidigital number, since it uses as much as digits as its factorization.

12201222110993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 35.

The spelling of 12201222110993 in words is "twelve trillion, two hundred one billion, two hundred twenty-two million, one hundred ten thousand, nine hundred ninety-three".