Base | Representation |
---|---|
bin | 10001110000010101000… |
… | …001001000101010010111 |
3 | 11022122100111022020212021 |
4 | 101300111001020222113 |
5 | 124442303033044343 |
6 | 2332303353234011 |
7 | 154102536124126 |
oct | 21602501105227 |
9 | 4278314266767 |
10 | 1220123331223 |
11 | 4304a68a2745 |
12 | 178574a02907 |
13 | 8b0986b48a4 |
14 | 430a8d55abd |
15 | 21b116b90ed |
hex | 11c15048a97 |
1220123331223 has 4 divisors (see below), whose sum is σ = 1220128630000. Its totient is φ = 1220118032448.
The previous prime is 1220123331181. The next prime is 1220123331283. The reversal of 1220123331223 is 3221333210221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1220123331223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1220123331283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2287515 + ... + 2770012.
It is an arithmetic number, because the mean of its divisors is an integer number (305032157500).
Almost surely, 21220123331223 is an apocalyptic number.
1220123331223 is a deficient number, since it is larger than the sum of its proper divisors (5298777).
1220123331223 is an equidigital number, since it uses as much as digits as its factorization.
1220123331223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5298776.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1220123331223 its reverse (3221333210221), we get a palindrome (4441456541444).
The spelling of 1220123331223 in words is "one trillion, two hundred twenty billion, one hundred twenty-three million, three hundred thirty-one thousand, two hundred twenty-three".
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