1220132021131 has 2 divisors, whose sum is σ = 1220132021132. Its totient is φ = 1220132021130.

The previous prime is 1220132021099. The next prime is 1220132021179. The reversal of 1220132021131 is 1311202310221.

It is a weak prime.

It is an emirp because it is prime and its reverse (1311202310221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1220132021131 - 2⁵ = 1220132021099 is a prime.

It is a super-2 number, since 2×1220132021131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1220132021099 and 1220132021108.

It is not a weakly prime, because it can be changed into another prime (1220132061131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610066010565 + 610066010566.

It is an arithmetic number, because the mean of its divisors is an integer number (610066010566).

Almost surely, 2^{1220132021131} is an apocalyptic number.

1220132021131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220132021131 is an equidigital number, since it uses as much as digits as its factorization.

1220132021131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1220132021131 its reverse (1311202310221), we get a palindrome (2531334331352).

The spelling of 1220132021131 in words is "one trillion, two hundred twenty billion, one hundred thirty-two million, twenty-one thousand, one hundred thirty-one".