Base | Representation |
---|---|
bin | 10001110000010101100… |
… | …110100001001101111011 |
3 | 11022122101011202010210211 |
4 | 101300111212201031323 |
5 | 124442313040144011 |
6 | 2332304343251551 |
7 | 154103015331235 |
oct | 21602546411573 |
9 | 4278334663724 |
10 | 1220133131131 |
11 | 430501386542 |
12 | 178578149bb7 |
13 | 8b09a736355 |
14 | 430aa387255 |
15 | 21b124a2b21 |
hex | 11c159a137b |
1220133131131 has 2 divisors, whose sum is σ = 1220133131132. Its totient is φ = 1220133131130.
The previous prime is 1220133131117. The next prime is 1220133131143. The reversal of 1220133131131 is 1311313310221.
It is a strong prime.
It is an emirp because it is prime and its reverse (1311313310221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1220133131131 - 27 = 1220133131003 is a prime.
It is a super-2 number, since 2×12201331311312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1220133131111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610066565565 + 610066565566.
It is an arithmetic number, because the mean of its divisors is an integer number (610066565566).
Almost surely, 21220133131131 is an apocalyptic number.
1220133131131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220133131131 is an equidigital number, since it uses as much as digits as its factorization.
1220133131131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1220133131131 its reverse (1311313310221), we get a palindrome (2531446441352).
The spelling of 1220133131131 in words is "one trillion, two hundred twenty billion, one hundred thirty-three million, one hundred thirty-one thousand, one hundred thirty-one".
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