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12202020133 is a prime number
BaseRepresentation
bin10110101110100110…
…00000110100100101
31011111101020211212121
423113103000310211
5144442204121013
65334443345541
7611243313502
oct132723006445
934441224777
1012202020133
1151a17a4366
1224465222b1
1311c5c78474
1483a7a84a9
154b637858d
hex2d74c0d25

12202020133 has 2 divisors, whose sum is σ = 12202020134. Its totient is φ = 12202020132.

The previous prime is 12202020119. The next prime is 12202020179. The reversal of 12202020133 is 33102020221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9955449729 + 2246570404 = 99777^2 + 47398^2 .

It is a cyclic number.

It is not a de Polignac number, because 12202020133 - 221 = 12199922981 is a prime.

It is a super-2 number, since 2×122020201332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12202020833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101010066 + 6101010067.

It is an arithmetic number, because the mean of its divisors is an integer number (6101010067).

Almost surely, 212202020133 is an apocalyptic number.

It is an amenable number.

12202020133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12202020133 is an equidigital number, since it uses as much as digits as its factorization.

12202020133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 12202020133 its reverse (33102020221), we get a palindrome (45304040354).

The spelling of 12202020133 in words is "twelve billion, two hundred two million, twenty thousand, one hundred thirty-three".