Base | Representation |
---|---|
bin | 111000110100110010… |
… | …1100010001110010011 |
3 | 102122222111222022000220 |
4 | 1301221211202032103 |
5 | 3444404304001400 |
6 | 132020545444123 |
7 | 11550013255146 |
oct | 1615145421623 |
9 | 378874868026 |
10 | 122030531475 |
11 | 47831065506 |
12 | 1b797940643 |
13 | b679a91598 |
14 | 5c98cac05d |
15 | 32933997a0 |
hex | 1c69962393 |
122030531475 has 12 divisors (see below), whose sum is σ = 201757145496. Its totient is φ = 65082950080.
The previous prime is 122030531437. The next prime is 122030531479. The reversal of 122030531475 is 574135030221.
It is not a de Polignac number, because 122030531475 - 217 = 122030400403 is a prime.
It is a super-2 number, since 2×1220305314752 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (122030531479) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 813536802 + ... + 813536951.
It is an arithmetic number, because the mean of its divisors is an integer number (16813095458).
Almost surely, 2122030531475 is an apocalyptic number.
122030531475 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
122030531475 is a deficient number, since it is larger than the sum of its proper divisors (79726614021).
122030531475 is a wasteful number, since it uses less digits than its factorization.
122030531475 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1627073766 (or 1627073761 counting only the distinct ones).
The product of its (nonzero) digits is 25200, while the sum is 33.
Adding to 122030531475 its reverse (574135030221), we get a palindrome (696165561696).
The spelling of 122030531475 in words is "one hundred twenty-two billion, thirty million, five hundred thirty-one thousand, four hundred seventy-five".
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