Base | Representation |
---|---|
bin | 10110101110101110… |
… | …01000011101011111 |
3 | 1011111110021201011122 |
4 | 23113113020131133 |
5 | 144442443144444 |
6 | 5334522441155 |
7 | 611255432006 |
oct | 132727103537 |
9 | 34443251148 |
10 | 12203099999 |
11 | 51a2371712 |
12 | 24469631bb |
13 | 11c6265b3c |
14 | 83a9a9c3d |
15 | 4b64dd4ee |
hex | 2d75c875f |
12203099999 has 4 divisors (see below), whose sum is σ = 12845368440. Its totient is φ = 11560831560.
The previous prime is 12203099963. The next prime is 12203100017. The reversal of 12203099999 is 99999030221.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 99999030221 = 14407 ⋅6941003.
It is a cyclic number.
It is not a de Polignac number, because 12203099999 - 220 = 12202051423 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12203099999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12203099099) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321134192 + ... + 321134229.
It is an arithmetic number, because the mean of its divisors is an integer number (3211342110).
Almost surely, 212203099999 is an apocalyptic number.
12203099999 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
12203099999 is a deficient number, since it is larger than the sum of its proper divisors (642268441).
12203099999 is an equidigital number, since it uses as much as digits as its factorization.
12203099999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 642268440.
The product of its (nonzero) digits is 708588, while the sum is 53.
The spelling of 12203099999 in words is "twelve billion, two hundred three million, ninety-nine thousand, nine hundred ninety-nine".
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