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12203120031300 = 223252113743774757
BaseRepresentation
bin1011000110010100001010…
…1000100111011001000100
31121012121101102020210121200
42301211002220213121010
53044413442212000200
641542011433142500
72366434455543462
oct261450250473104
947177342223550
1012203120031300
113985350139770
12145106825aa30
136a699822b513
143028c41cd832
15162670248800
hexb1942a27644

12203120031300 has 432 divisors, whose sum is σ = 43851724268352. Its totient is φ = 2811434572800.

The previous prime is 12203120031247. The next prime is 12203120031317. The reversal of 12203120031300 is 313002130221.

12203120031300 is a `hidden beast` number, since 1 + 2 + 20 + 312 + 0 + 0 + 31 + 300 = 666.

It is a super-2 number, since 2×122031200313002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 15363522 + ... + 16138278.

Almost surely, 212203120031300 is an apocalyptic number.

12203120031300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12203120031300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21925862134176).

12203120031300 is an abundant number, since it is smaller than the sum of its proper divisors (31648604237052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12203120031300 is a wasteful number, since it uses less digits than its factorization.

12203120031300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 774868 (or 774858 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 12203120031300 its reverse (313002130221), we get a palindrome (12516122161521).

It can be divided in two parts, 122031200 and 31300, that added together give a triangular number (122062500 = T15624).

The spelling of 12203120031300 in words is "twelve trillion, two hundred three billion, one hundred twenty million, thirty-one thousand, three hundred".