Base | Representation |
---|---|
bin | 1011000110010100001010… |
… | …1000100111011001000100 |
3 | 1121012121101102020210121200 |
4 | 2301211002220213121010 |
5 | 3044413442212000200 |
6 | 41542011433142500 |
7 | 2366434455543462 |
oct | 261450250473104 |
9 | 47177342223550 |
10 | 12203120031300 |
11 | 3985350139770 |
12 | 145106825aa30 |
13 | 6a699822b513 |
14 | 3028c41cd832 |
15 | 162670248800 |
hex | b1942a27644 |
12203120031300 has 432 divisors, whose sum is σ = 43851724268352. Its totient is φ = 2811434572800.
The previous prime is 12203120031247. The next prime is 12203120031317. The reversal of 12203120031300 is 313002130221.
12203120031300 is a `hidden beast` number, since 1 + 2 + 20 + 312 + 0 + 0 + 31 + 300 = 666.
It is a super-2 number, since 2×122031200313002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 15363522 + ... + 16138278.
Almost surely, 212203120031300 is an apocalyptic number.
12203120031300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12203120031300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21925862134176).
12203120031300 is an abundant number, since it is smaller than the sum of its proper divisors (31648604237052).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12203120031300 is a wasteful number, since it uses less digits than its factorization.
12203120031300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 774868 (or 774858 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 12203120031300 its reverse (313002130221), we get a palindrome (12516122161521).
It can be divided in two parts, 122031200 and 31300, that added together give a triangular number (122062500 = T15624).
The spelling of 12203120031300 in words is "twelve trillion, two hundred three billion, one hundred twenty million, thirty-one thousand, three hundred".
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