Base | Representation |
---|---|
bin | 1011000110010100100101… |
… | …0100111011001101100001 |
3 | 1121012121200020112011012020 |
4 | 2301211021110323031201 |
5 | 3044414204432410423 |
6 | 41542030523452053 |
7 | 2366440321106115 |
oct | 261451124731541 |
9 | 47177606464166 |
10 | 12203232310113 |
11 | 39853a8557479 |
12 | 1451099987029 |
13 | 6a69b5580ba0 |
14 | 3028d5099745 |
15 | 16267a0264e3 |
hex | b194953b361 |
12203232310113 has 32 divisors (see below), whose sum is σ = 18285980676096. Its totient is φ = 7182568945728.
The previous prime is 12203232310099. The next prime is 12203232310123. The reversal of 12203232310113 is 31101323230221.
It is not a de Polignac number, because 12203232310113 - 29 = 12203232309601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12203232310123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10203756 + ... + 11336802.
It is an arithmetic number, because the mean of its divisors is an integer number (571436896128).
Almost surely, 212203232310113 is an apocalyptic number.
12203232310113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12203232310113 is a deficient number, since it is larger than the sum of its proper divisors (6082748365983).
12203232310113 is a wasteful number, since it uses less digits than its factorization.
12203232310113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1145093.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 12203232310113 its reverse (31101323230221), we get a palindrome (43304555540334).
The spelling of 12203232310113 in words is "twelve trillion, two hundred three billion, two hundred thirty-two million, three hundred ten thousand, one hundred thirteen".
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